(5w-3)(5-w)=0

Solution for (5w-3)(5-w)=0 equation:

(5w-3)(5-w)=0

We add all the numbers together, and all the variables

(5w-3)(-1w+5)=0

We multiply parentheses ..

(-5w^2+25w+3w-15)=0

We get rid of parentheses

-5w^2+25w+3w-15=0

We add all the numbers together, and all the variables

-5w^2+28w-15=0

a = -5; b = 28; c = -15;
Δ = b2-4ac
Δ = 282-4·(-5)·(-15)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-22}{2*-5}=\frac{-50}{-10}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+22}{2*-5}=\frac{-6}{-10}
=3/5
$