(5w-3)(w+9)=0

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Solution for (5w-3)(w+9)=0 equation:



(5w-3)(w+9)=0
We multiply parentheses ..
(+5w^2+45w-3w-27)=0
We get rid of parentheses
5w^2+45w-3w-27=0
We add all the numbers together, and all the variables
5w^2+42w-27=0
a = 5; b = 42; c = -27;
Δ = b2-4ac
Δ = 422-4·5·(-27)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-48}{2*5}=\frac{-90}{10} =-9 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+48}{2*5}=\frac{6}{10} =3/5 $

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