(5w-3)(w+9)=0

Solution for (5w-3)(w+9)=0 equation:

(5w-3)(w+9)=0

We multiply parentheses ..

(+5w^2+45w-3w-27)=0

We get rid of parentheses

5w^2+45w-3w-27=0

We add all the numbers together, and all the variables

5w^2+42w-27=0

a = 5; b = 42; c = -27;
Δ = b2-4ac
Δ = 422-4·5·(-27)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-48}{2*5}=\frac{-90}{10}
=-9
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+48}{2*5}=\frac{6}{10}
=3/5
$