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(5x)(25x+30)=180
We move all terms to the left:
(5x)(25x+30)-(180)=0
We multiply parentheses
125x^2+150x-180=0
a = 125; b = 150; c = -180;
Δ = b2-4ac
Δ = 1502-4·125·(-180)
Δ = 112500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112500}=\sqrt{22500*5}=\sqrt{22500}*\sqrt{5}=150\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150\sqrt{5}}{2*125}=\frac{-150-150\sqrt{5}}{250} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150\sqrt{5}}{2*125}=\frac{-150+150\sqrt{5}}{250} $
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