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(5x)(3x+12)=90
We move all terms to the left:
(5x)(3x+12)-(90)=0
We multiply parentheses
15x^2+60x-90=0
a = 15; b = 60; c = -90;
Δ = b2-4ac
Δ = 602-4·15·(-90)
Δ = 9000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9000}=\sqrt{900*10}=\sqrt{900}*\sqrt{10}=30\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-30\sqrt{10}}{2*15}=\frac{-60-30\sqrt{10}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+30\sqrt{10}}{2*15}=\frac{-60+30\sqrt{10}}{30} $
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