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(5x)(3x=28)
We move all terms to the left:
(5x)(3x-(28))=0
We multiply parentheses
15x^2-140x=0
a = 15; b = -140; c = 0;
Δ = b2-4ac
Δ = -1402-4·15·0
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-140}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+140}{2*15}=\frac{280}{30} =9+1/3 $
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