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(5x)(6x+4)=180
We move all terms to the left:
(5x)(6x+4)-(180)=0
We multiply parentheses
30x^2+20x-180=0
a = 30; b = 20; c = -180;
Δ = b2-4ac
Δ = 202-4·30·(-180)
Δ = 22000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22000}=\sqrt{400*55}=\sqrt{400}*\sqrt{55}=20\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{55}}{2*30}=\frac{-20-20\sqrt{55}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{55}}{2*30}=\frac{-20+20\sqrt{55}}{60} $
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