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(5x)+(x-3)=125
We move all terms to the left:
(5x)+(x-3)-(125)=0
We get rid of parentheses
5x+x-3-125=0
We add all the numbers together, and all the variables
6x-128=0
We move all terms containing x to the left, all other terms to the right
6x=128
x=128/6
x=21+1/3
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