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(5x)/7=(2x-4)/3
We move all terms to the left:
(5x)/7-((2x-4)/3)=0
We calculate fractions
15x^2/()+(-((2x-4)*7)/()=0
We calculate terms in parentheses: +(-((2x-4)*7)/(), so:We get rid of parentheses
-((2x-4)*7)/(
We multiply all the terms by the denominator
-((2x-4)*7)
We calculate terms in parentheses: -((2x-4)*7), so:We get rid of parentheses
(2x-4)*7
We multiply parentheses
14x-28
Back to the equation:
-(14x-28)
-14x+28
Back to the equation:
+(-14x+28)
15x^2/()-14x+28=0
We multiply all the terms by the denominator
15x^2-14x*()+28*()=0
We add all the numbers together, and all the variables
15x^2-14x*()=0
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