(5x)=(6x-10)x=

Solution for (5x)=(6x-10)x= equation:

(5x)=(6x-10)x=

We move all terms to the left:

(5x)-((6x-10)x)=0


We calculate terms in parentheses: -((6x-10)x), so:

(6x-10)x

We multiply parentheses

6x^2-10x

Back to the equation:

-(6x^2-10x)


We get rid of parentheses

-6x^2+5x+10x=0

We add all the numbers together, and all the variables

-6x^2+15x=0

a = -6; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-6)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-6}=\frac{-30}{-12}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-6}=\frac{0}{-12}
=0
$