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(5x*x)-26=0
We add all the numbers together, and all the variables
(+5x*x)-26=0
We get rid of parentheses
5x*x-26=0
Wy multiply elements
5x^2-26=0
a = 5; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·5·(-26)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{130}}{2*5}=\frac{0-2\sqrt{130}}{10} =-\frac{2\sqrt{130}}{10} =-\frac{\sqrt{130}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{130}}{2*5}=\frac{0+2\sqrt{130}}{10} =\frac{2\sqrt{130}}{10} =\frac{\sqrt{130}}{5} $
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