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(5x+1)(2x-1)+(5x+1)(5x+1)=0
We multiply parentheses ..
(+10x^2-5x+2x-1)+(5x+1)(5x+1)=0
We get rid of parentheses
10x^2-5x+2x+(5x+1)(5x+1)-1=0
We multiply parentheses ..
10x^2+(+25x^2+5x+5x+1)-5x+2x-1=0
We add all the numbers together, and all the variables
10x^2+(+25x^2+5x+5x+1)-3x-1=0
We get rid of parentheses
10x^2+25x^2+5x+5x-3x+1-1=0
We add all the numbers together, and all the variables
35x^2+7x=0
a = 35; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·35·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*35}=\frac{-14}{70} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*35}=\frac{0}{70} =0 $
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