(5x+1)/3=(9x-7)/11

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Solution for (5x+1)/3=(9x-7)/11 equation: 



(5x+1)/3=(9x-7)/11

We move all terms to the left:

(5x+1)/3-((9x-7)/11)=0

We calculate fractions


5x/()+(-((9x-7)*3)/()=0



We calculate terms in parentheses: +(-((9x-7)*3)/(), so:

-((9x-7)*3)/(

We multiply all the terms by the denominator


-((9x-7)*3)



We calculate terms in parentheses: -((9x-7)*3), so:

(9x-7)*3

We multiply parentheses

27x-21

Back to the equation:

-(27x-21)



We get rid of parentheses

-27x+21

Back to the equation:

+(-27x+21)



We get rid of parentheses

5x/()-27x+21=0

We multiply all the terms by the denominator


5x-27x*()+21*()=0

We add all the numbers together, and all the variables

5x-27x*()=0

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