(5x+1)/x(x-2)+3/(2-x)=1/(4x)

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Solution for (5x+1)/x(x-2)+3/(2-x)=1/(4x) equation: 



(5x+1)/x(x-2)+3/(2-x)=1/(4x)

We move all terms to the left:

(5x+1)/x(x-2)+3/(2-x)-(1/(4x))=0



Domain of the equation: x(x-2)!=0

x∈R





Domain of the equation: (2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-2

x!=-2/-1

x!=+2

x∈R





Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(5x+1)/x(x-2)+3/(-1x+2)-(+1/4x)=0

We get rid of parentheses

(5x+1)/x(x-2)+3/(-1x+2)-1/4x=0

We calculate fractions


(12x^2x/(x(x-2)*(-1x+2)*4x)+(-1x^2x/(x(x-2)*(-1x+2)*4x)+((5x+1)*(-1x+2)*4x)/(x(x-2)*(-1x+2)*4x)=0



We calculate terms in parentheses: +(12x^2x/(x(x-2)*(-1x+2)*4x)+(-1x^2x/(x(x-2)*(-1x+2)*4x)+((5x+1)*(-1x+2)*4x)/(x(x-2)*(-1x+2)*4x), so:

12x^2x/(x(x-2)*(-1x+2)*4x)+(-1x^2x/(x(x-2)*(-1x+2)*4x)+((5x+1)*(-1x+2)*4x)/(x(x-2)*(-1x+2)*4x

We can not solve this equation

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