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(5x+10)(3x+10)=180
We move all terms to the left:
(5x+10)(3x+10)-(180)=0
We multiply parentheses ..
(+15x^2+50x+30x+100)-180=0
We get rid of parentheses
15x^2+50x+30x+100-180=0
We add all the numbers together, and all the variables
15x^2+80x-80=0
a = 15; b = 80; c = -80;
Δ = b2-4ac
Δ = 802-4·15·(-80)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40\sqrt{7}}{2*15}=\frac{-80-40\sqrt{7}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40\sqrt{7}}{2*15}=\frac{-80+40\sqrt{7}}{30} $
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