(5x+10)-logx=2

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Solution for (5x+10)-logx=2 equation:


Simplifying
(5x + 10) + -1logx = 2

Reorder the terms:
(10 + 5x) + -1logx = 2

Remove parenthesis around (10 + 5x)
10 + 5x + -1logx = 2

Reorder the terms:
10 + -1glox + 5x = 2

Solving
10 + -1glox + 5x = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -1glox + -10 + 5x = 2 + -10

Reorder the terms:
10 + -10 + -1glox + 5x = 2 + -10

Combine like terms: 10 + -10 = 0
0 + -1glox + 5x = 2 + -10
-1glox + 5x = 2 + -10

Combine like terms: 2 + -10 = -8
-1glox + 5x = -8

Add '-5x' to each side of the equation.
-1glox + 5x + -5x = -8 + -5x

Combine like terms: 5x + -5x = 0
-1glox + 0 = -8 + -5x
-1glox = -8 + -5x

Divide each side by '-1lox'.
g = 8l-1o-1x-1 + 5l-1o-1

Simplifying
g = 8l-1o-1x-1 + 5l-1o-1

Reorder the terms:
g = 5l-1o-1 + 8l-1o-1x-1

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