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(5x+10)/(2x+2)=2
We move all terms to the left:
(5x+10)/(2x+2)-(2)=0
Domain of the equation: (2x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=-2
x!=-2/2
x!=-1
x∈R
(5x+10)-2*(2x+2)=0
We multiply parentheses
(5x+10)-4x-4=0
We get rid of parentheses
5x-4x+10-4=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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