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(5x+100)=(3x+112)
We move all terms to the left:
(5x+100)-((3x+112))=0
We get rid of parentheses
5x-((3x+112))+100=0
We calculate terms in parentheses: -((3x+112)), so:We get rid of parentheses
(3x+112)
We get rid of parentheses
3x+112
Back to the equation:
-(3x+112)
5x-3x-112+100=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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