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(5x+11=x-5.x)
We move all terms to the left:
(5x+11-(x-5.x))=0
We add all the numbers together, and all the variables
(5x+11-(-4x))=0
We calculate terms in parentheses: +(5x+11-(-4x)), so:We get rid of parentheses
5x+11-(-4x)
determiningTheFunctionDomain 5x-(-4x)+11
We get rid of parentheses
5x+4x+11
We add all the numbers together, and all the variables
9x+11
Back to the equation:
+(9x+11)
9x+11=0
We move all terms containing x to the left, all other terms to the right
9x=-11
x=-11/9
x=-1+2/9
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