(5x+12)+(6x-10)+(x+20)=180

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Solution for (5x+12)+(6x-10)+(x+20)=180 equation:



(5x+12)+(6x-10)+(x+20)=180
We move all terms to the left:
(5x+12)+(6x-10)+(x+20)-(180)=0
We get rid of parentheses
5x+6x+x+12-10+20-180=0
We add all the numbers together, and all the variables
12x-158=0
We move all terms containing x to the left, all other terms to the right
12x=158
x=158/12
x=13+1/6

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