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(5x+13)+(3x+14)=(2x+51)
We move all terms to the left:
(5x+13)+(3x+14)-((2x+51))=0
We get rid of parentheses
5x+3x-((2x+51))+13+14=0
We calculate terms in parentheses: -((2x+51)), so:We add all the numbers together, and all the variables
(2x+51)
We get rid of parentheses
2x+51
Back to the equation:
-(2x+51)
8x-(2x+51)+27=0
We get rid of parentheses
8x-2x-51+27=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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