(5x+15)(5x-15)=0

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Solution for (5x+15)(5x-15)=0 equation:



(5x+15)(5x-15)=0
We use the square of the difference formula
25x^2-225=0
a = 25; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·25·(-225)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*25}=\frac{-150}{50} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*25}=\frac{150}{50} =3 $

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