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(5x+15)=(45)
We move all terms to the left:
(5x+15)-((45))=0
determiningTheFunctionDomain (5x+15)-45=0
We get rid of parentheses
5x+15-45=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6
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