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(5x+2)(3x+3)=
We move all terms to the left:
(5x+2)(3x+3)-()=0
We add all the numbers together, and all the variables
(5x+2)(3x+3)=0
We multiply parentheses ..
(+15x^2+15x+6x+6)=0
We get rid of parentheses
15x^2+15x+6x+6=0
We add all the numbers together, and all the variables
15x^2+21x+6=0
a = 15; b = 21; c = +6;
Δ = b2-4ac
Δ = 212-4·15·6
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*15}=\frac{-30}{30} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*15}=\frac{-12}{30} =-2/5 $
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