(5x+2)(5x-2)=25x-4

Solution for (5x+2)(5x-2)=25x-4 equation:

(5x+2)(5x-2)=25x-4

We move all terms to the left:

(5x+2)(5x-2)-(25x-4)=0

We use the square of the difference formula

25x^2-(25x-4)-4=0

We get rid of parentheses

25x^2-25x+4-4=0

We add all the numbers together, and all the variables

25x^2-25x=0

a = 25; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·25·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*25}=\frac{0}{50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*25}=\frac{50}{50}
=1
$