(5x+2)(x+1)=0

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Solution for (5x+2)(x+1)=0 equation:


Simplifying
(5x + 2)(x + 1) = 0

Reorder the terms:
(2 + 5x)(x + 1) = 0

Reorder the terms:
(2 + 5x)(1 + x) = 0

Multiply (2 + 5x) * (1 + x)
(2(1 + x) + 5x * (1 + x)) = 0
((1 * 2 + x * 2) + 5x * (1 + x)) = 0
((2 + 2x) + 5x * (1 + x)) = 0
(2 + 2x + (1 * 5x + x * 5x)) = 0
(2 + 2x + (5x + 5x2)) = 0

Combine like terms: 2x + 5x = 7x
(2 + 7x + 5x2) = 0

Solving
2 + 7x + 5x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + x)(2 + 5x) = 0

Subproblem 1

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Subproblem 2

Set the factor '(2 + 5x)' equal to zero and attempt to solve: Simplifying 2 + 5x = 0 Solving 2 + 5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5x = 0 + -2 5x = 0 + -2 Combine like terms: 0 + -2 = -2 5x = -2 Divide each side by '5'. x = -0.4 Simplifying x = -0.4

Solution

x = {-1, -0.4}

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