(5x+2)(x+7)=0

Solution for (5x+2)(x+7)=0 equation:

(5x+2)(x+7)=0

We multiply parentheses ..

(+5x^2+35x+2x+14)=0

We get rid of parentheses

5x^2+35x+2x+14=0

We add all the numbers together, and all the variables

5x^2+37x+14=0

a = 5; b = 37; c = +14;
Δ = b2-4ac
Δ = 372-4·5·14
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-33}{2*5}=\frac{-70}{10}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+33}{2*5}=\frac{-4}{10}
=-2/5
$