(5x+2)(x-1)=7(x-1)

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Solution for (5x+2)(x-1)=7(x-1) equation:


Simplifying
(5x + 2)(x + -1) = 7(x + -1)

Reorder the terms:
(2 + 5x)(x + -1) = 7(x + -1)

Reorder the terms:
(2 + 5x)(-1 + x) = 7(x + -1)

Multiply (2 + 5x) * (-1 + x)
(2(-1 + x) + 5x * (-1 + x)) = 7(x + -1)
((-1 * 2 + x * 2) + 5x * (-1 + x)) = 7(x + -1)
((-2 + 2x) + 5x * (-1 + x)) = 7(x + -1)
(-2 + 2x + (-1 * 5x + x * 5x)) = 7(x + -1)
(-2 + 2x + (-5x + 5x2)) = 7(x + -1)

Combine like terms: 2x + -5x = -3x
(-2 + -3x + 5x2) = 7(x + -1)

Reorder the terms:
-2 + -3x + 5x2 = 7(-1 + x)
-2 + -3x + 5x2 = (-1 * 7 + x * 7)
-2 + -3x + 5x2 = (-7 + 7x)

Solving
-2 + -3x + 5x2 = -7 + 7x

Solving for variable 'x'.

Reorder the terms:
-2 + 7 + -3x + -7x + 5x2 = -7 + 7x + 7 + -7x

Combine like terms: -2 + 7 = 5
5 + -3x + -7x + 5x2 = -7 + 7x + 7 + -7x

Combine like terms: -3x + -7x = -10x
5 + -10x + 5x2 = -7 + 7x + 7 + -7x

Reorder the terms:
5 + -10x + 5x2 = -7 + 7 + 7x + -7x

Combine like terms: -7 + 7 = 0
5 + -10x + 5x2 = 0 + 7x + -7x
5 + -10x + 5x2 = 7x + -7x

Combine like terms: 7x + -7x = 0
5 + -10x + 5x2 = 0

Factor out the Greatest Common Factor (GCF), '5'.
5(1 + -2x + x2) = 0

Factor a trinomial.
5((1 + -1x)(1 + -1x)) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {1, 1}

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