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(5x+2)(x-6)=180
We move all terms to the left:
(5x+2)(x-6)-(180)=0
We multiply parentheses ..
(+5x^2-30x+2x-12)-180=0
We get rid of parentheses
5x^2-30x+2x-12-180=0
We add all the numbers together, and all the variables
5x^2-28x-192=0
a = 5; b = -28; c = -192;
Δ = b2-4ac
Δ = -282-4·5·(-192)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-68}{2*5}=\frac{-40}{10} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+68}{2*5}=\frac{96}{10} =9+3/5 $
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