(5x+2)+(7/5)=1

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Solution for (5x+2)+(7/5)=1 equation: 



(5x+2)+(7/5)=1

We move all terms to the left:

(5x+2)+(7/5)-(1)=0

determiningTheFunctionDomain
(5x+2)-1+(7/5)=0

We add all the numbers together, and all the variables

(5x+2)-1+(+7/5)=0

We get rid of parentheses

5x+2-1+7/5=0

We multiply all the terms by the denominator


5x*5+7+2*5-1*5=0

We add all the numbers together, and all the variables

5x*5+12=0

Wy multiply elements

25x+12=0

We move all terms containing x to the left, all other terms to the right

25x=-12

x=-12/25

x=-12/25

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