(5x+2)-(-x-4)=(3x+5)+(x-3)

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Solution for (5x+2)-(-x-4)=(3x+5)+(x-3) equation: 



(5x+2)-(-x-4)=(3x+5)+(x-3)

We move all terms to the left:

(5x+2)-(-x-4)-((3x+5)+(x-3))=0

We add all the numbers together, and all the variables

(5x+2)-(-1x-4)-((3x+5)+(x-3))=0

We get rid of parentheses

5x+1x-((3x+5)+(x-3))+2+4=0



We calculate terms in parentheses: -((3x+5)+(x-3)), so:

(3x+5)+(x-3)

We get rid of parentheses

3x+x+5-3

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

6x-(4x+2)+6=0

We get rid of parentheses

6x-4x-2+6=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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