(5x+2)/7=(1+2x)/2

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Solution for (5x+2)/7=(1+2x)/2 equation: 



(5x+2)/7=(1+2x)/2

We move all terms to the left:

(5x+2)/7-((1+2x)/2)=0

We add all the numbers together, and all the variables

(5x+2)/7-((2x+1)/2)=0

We calculate fractions


5x/()+(-((2x+1)*7)/()=0



We calculate terms in parentheses: +(-((2x+1)*7)/(), so:

-((2x+1)*7)/(

We multiply all the terms by the denominator


-((2x+1)*7)



We calculate terms in parentheses: -((2x+1)*7), so:

(2x+1)*7

We multiply parentheses

14x+7

Back to the equation:

-(14x+7)



We get rid of parentheses

-14x-7

Back to the equation:

+(-14x-7)



We get rid of parentheses

5x/()-14x-7=0

We multiply all the terms by the denominator


5x-14x*()-7*()=0

We add all the numbers together, and all the variables

5x-14x*()=0

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