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(5x+2)3x=90
We move all terms to the left:
(5x+2)3x-(90)=0
We multiply parentheses
15x^2+6x-90=0
a = 15; b = 6; c = -90;
Δ = b2-4ac
Δ = 62-4·15·(-90)
Δ = 5436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5436}=\sqrt{36*151}=\sqrt{36}*\sqrt{151}=6\sqrt{151}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{151}}{2*15}=\frac{-6-6\sqrt{151}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{151}}{2*15}=\frac{-6+6\sqrt{151}}{30} $
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