(5x+2)6x+134=180

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Solution for (5x+2)6x+134=180 equation:



(5x+2)6x+134=180
We move all terms to the left:
(5x+2)6x+134-(180)=0
We add all the numbers together, and all the variables
(5x+2)6x-46=0
We multiply parentheses
30x^2+12x-46=0
a = 30; b = 12; c = -46;
Δ = b2-4ac
Δ = 122-4·30·(-46)
Δ = 5664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5664}=\sqrt{16*354}=\sqrt{16}*\sqrt{354}=4\sqrt{354}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{354}}{2*30}=\frac{-12-4\sqrt{354}}{60} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{354}}{2*30}=\frac{-12+4\sqrt{354}}{60} $

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