(5x+2)=(10x-3)=(7x-11)=(8x-19)=(13x-31)

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Solution for (5x+2)=(10x-3)=(7x-11)=(8x-19)=(13x-31) equation: 



(5x+2)=(10x-3)=(7x-11)=(8x-19)=(13x-31)

We move all terms to the left:

(5x+2)-((10x-3))=0

We get rid of parentheses

5x-((10x-3))+2=0



We calculate terms in parentheses: -((10x-3)), so:

(10x-3)

We get rid of parentheses

10x-3

Back to the equation:

-(10x-3)



We get rid of parentheses

5x-10x+3+2=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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