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(5x+20)(3x-12)=0
We multiply parentheses ..
(+15x^2-60x+60x-240)=0
We get rid of parentheses
15x^2-60x+60x-240=0
We add all the numbers together, and all the variables
15x^2-240=0
a = 15; b = 0; c = -240;
Δ = b2-4ac
Δ = 02-4·15·(-240)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*15}=\frac{-120}{30} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*15}=\frac{120}{30} =4 $
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