(5x+20)+(3x+40)=(9x+44)

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Solution for (5x+20)+(3x+40)=(9x+44) equation: 



(5x+20)+(3x+40)=(9x+44)

We move all terms to the left:

(5x+20)+(3x+40)-((9x+44))=0

We get rid of parentheses

5x+3x-((9x+44))+20+40=0



We calculate terms in parentheses: -((9x+44)), so:

(9x+44)

We get rid of parentheses

9x+44

Back to the equation:

-(9x+44)



We add all the numbers together, and all the variables

8x-(9x+44)+60=0

We get rid of parentheses

8x-9x-44+60=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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