(5x+20)3x=3x(9x-92)

Solution for (5x+20)3x=3x(9x-92) equation:

(5x+20)3x=3x(9x-92)

We move all terms to the left:

(5x+20)3x-(3x(9x-92))=0

We multiply parentheses

15x^2+60x-(3x(9x-92))=0


We calculate terms in parentheses: -(3x(9x-92)), so:

3x(9x-92)

We multiply parentheses

27x^2-276x

Back to the equation:

-(27x^2-276x)


We get rid of parentheses

15x^2-27x^2+60x+276x=0

We add all the numbers together, and all the variables

-12x^2+336x=0

a = -12; b = 336; c = 0;
Δ = b2-4ac
Δ = 3362-4·(-12)·0
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{112896}=336$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-336}{2*-12}=\frac{-672}{-24}
=+28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+336}{2*-12}=\frac{0}{-24}
=0
$