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(5x+25)(x-8)=60(x+5)
We move all terms to the left:
(5x+25)(x-8)-(60(x+5))=0
We multiply parentheses ..
(+5x^2-40x+25x-200)-(60(x+5))=0
We calculate terms in parentheses: -(60(x+5)), so:We get rid of parentheses
60(x+5)
We multiply parentheses
60x+300
Back to the equation:
-(60x+300)
5x^2-40x+25x-60x-200-300=0
We add all the numbers together, and all the variables
5x^2-75x-500=0
a = 5; b = -75; c = -500;
Δ = b2-4ac
Δ = -752-4·5·(-500)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15625}=125$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-125}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+125}{2*5}=\frac{200}{10} =20 $
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