(5x+27)x=11

Solution for (5x+27)x=11 equation:

(5x+27)x=11

We move all terms to the left:

(5x+27)x-(11)=0

We multiply parentheses

5x^2+27x-11=0

a = 5; b = 27; c = -11;
Δ = b2-4ac
Δ = 272-4·5·(-11)
Δ = 949
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{949}}{2*5}=\frac{-27-\sqrt{949}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{949}}{2*5}=\frac{-27+\sqrt{949}}{10}
$