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(5x+2=3x+10)
We move all terms to the left:
(5x+2-(3x+10))=0
We calculate terms in parentheses: +(5x+2-(3x+10)), so:We get rid of parentheses
5x+2-(3x+10)
determiningTheFunctionDomain 5x-(3x+10)+2
We get rid of parentheses
5x-3x-10+2
We add all the numbers together, and all the variables
2x-8
Back to the equation:
+(2x-8)
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4
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