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(5x+3)(10x-2)=56x
We move all terms to the left:
(5x+3)(10x-2)-(56x)=0
We add all the numbers together, and all the variables
-56x+(5x+3)(10x-2)=0
We multiply parentheses ..
(+50x^2-10x+30x-6)-56x=0
We get rid of parentheses
50x^2-10x+30x-56x-6=0
We add all the numbers together, and all the variables
50x^2-36x-6=0
a = 50; b = -36; c = -6;
Δ = b2-4ac
Δ = -362-4·50·(-6)
Δ = 2496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2496}=\sqrt{64*39}=\sqrt{64}*\sqrt{39}=8\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-8\sqrt{39}}{2*50}=\frac{36-8\sqrt{39}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+8\sqrt{39}}{2*50}=\frac{36+8\sqrt{39}}{100} $
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