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(5x+3)(4x+3)=11/9
We move all terms to the left:
(5x+3)(4x+3)-(11/9)=0
We add all the numbers together, and all the variables
(5x+3)(4x+3)-(+11/9)=0
We get rid of parentheses
(5x+3)(4x+3)-11/9=0
We multiply parentheses ..
(+20x^2+15x+12x+9)-11/9=0
We multiply all the terms by the denominator
((+20x^2+15x+12x+9))*9-11=0
We move all terms containing x to the left, all other terms to the right
((+20x^2+15x+12x+9))*9=11
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