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(5x+3)(4x-1)=112
We move all terms to the left:
(5x+3)(4x-1)-(112)=0
We multiply parentheses ..
(+20x^2-5x+12x-3)-112=0
We get rid of parentheses
20x^2-5x+12x-3-112=0
We add all the numbers together, and all the variables
20x^2+7x-115=0
a = 20; b = 7; c = -115;
Δ = b2-4ac
Δ = 72-4·20·(-115)
Δ = 9249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{9249}}{2*20}=\frac{-7-\sqrt{9249}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{9249}}{2*20}=\frac{-7+\sqrt{9249}}{40} $
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