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(5x+3)/(4x+3)=11/9
We move all terms to the left:
(5x+3)/(4x+3)-(11/9)=0
Domain of the equation: (4x+3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x!=-3
x!=-3/4
x!=-3/4
x∈R
(5x+3)/(4x+3)-(+11/9)=0
We get rid of parentheses
(5x+3)/(4x+3)-11/9=0
We calculate fractions
(45x+27)/(36x+27)+(-44x-33)/(36x+27)=0
We multiply all the terms by the denominator
(45x+27)+(-44x-33)=0
We get rid of parentheses
45x-44x+27-33=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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