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(5x+3)/(x+1)=0
Domain of the equation: (x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(5x+3)=0
We get rid of parentheses
5x+3=0
We move all terms containing x to the left, all other terms to the right
5x=-3
x=-3/5
x=-3/5
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