(5x+3)/5=(7-2x)/3

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Solution for (5x+3)/5=(7-2x)/3 equation: 



(5x+3)/5=(7-2x)/3

We move all terms to the left:

(5x+3)/5-((7-2x)/3)=0

We add all the numbers together, and all the variables

(5x+3)/5-((-2x+7)/3)=0

We calculate fractions


5x/()+(-((-2x+7)*5)/()=0



We calculate terms in parentheses: +(-((-2x+7)*5)/(), so:

-((-2x+7)*5)/(

We multiply all the terms by the denominator


-((-2x+7)*5)



We calculate terms in parentheses: -((-2x+7)*5), so:

(-2x+7)*5

We multiply parentheses

-10x+35

Back to the equation:

-(-10x+35)



We get rid of parentheses

10x-35

Back to the equation:

+(10x-35)



We get rid of parentheses

5x/()+10x-35=0

We multiply all the terms by the denominator


5x+10x*()-35*()=0

We add all the numbers together, and all the variables

5x+10x*()=0

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