(5x+3)/6=(3x-1)/5

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Solution for (5x+3)/6=(3x-1)/5 equation:



(5x+3)/6=(3x-1)/5
We move all terms to the left:
(5x+3)/6-((3x-1)/5)=0
We calculate fractions
5x/()+(-((3x-1)*6)/()=0
We calculate terms in parentheses: +(-((3x-1)*6)/(), so:
-((3x-1)*6)/(
We multiply all the terms by the denominator
-((3x-1)*6)
We calculate terms in parentheses: -((3x-1)*6), so:
(3x-1)*6
We multiply parentheses
18x-6
Back to the equation:
-(18x-6)
We get rid of parentheses
-18x+6
Back to the equation:
+(-18x+6)
We get rid of parentheses
5x/()-18x+6=0
We multiply all the terms by the denominator
5x-18x*()+6*()=0
We add all the numbers together, and all the variables
5x-18x*()=0

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