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(5x+30)(2x)=180
We move all terms to the left:
(5x+30)(2x)-(180)=0
We multiply parentheses
10x^2+60x-180=0
a = 10; b = 60; c = -180;
Δ = b2-4ac
Δ = 602-4·10·(-180)
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{3}}{2*10}=\frac{-60-60\sqrt{3}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{3}}{2*10}=\frac{-60+60\sqrt{3}}{20} $
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