(5x+32)(x+4)=0

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Solution for (5x+32)(x+4)=0 equation:


Simplifying
(5x + 32)(x + 4) = 0

Reorder the terms:
(32 + 5x)(x + 4) = 0

Reorder the terms:
(32 + 5x)(4 + x) = 0

Multiply (32 + 5x) * (4 + x)
(32(4 + x) + 5x * (4 + x)) = 0
((4 * 32 + x * 32) + 5x * (4 + x)) = 0
((128 + 32x) + 5x * (4 + x)) = 0
(128 + 32x + (4 * 5x + x * 5x)) = 0
(128 + 32x + (20x + 5x2)) = 0

Combine like terms: 32x + 20x = 52x
(128 + 52x + 5x2) = 0

Solving
128 + 52x + 5x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(32 + 5x)(4 + x) = 0

Subproblem 1

Set the factor '(32 + 5x)' equal to zero and attempt to solve: Simplifying 32 + 5x = 0 Solving 32 + 5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-32' to each side of the equation. 32 + -32 + 5x = 0 + -32 Combine like terms: 32 + -32 = 0 0 + 5x = 0 + -32 5x = 0 + -32 Combine like terms: 0 + -32 = -32 5x = -32 Divide each side by '5'. x = -6.4 Simplifying x = -6.4

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {-6.4, -4}

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