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(5x+4)(8x+7)=0
We multiply parentheses ..
(+40x^2+35x+32x+28)=0
We get rid of parentheses
40x^2+35x+32x+28=0
We add all the numbers together, and all the variables
40x^2+67x+28=0
a = 40; b = 67; c = +28;
Δ = b2-4ac
Δ = 672-4·40·28
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-3}{2*40}=\frac{-70}{80} =-7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+3}{2*40}=\frac{-64}{80} =-4/5 $
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